2017 April 27 Python

关于zip

zip遍历两个长度相等的可迭代对象

    names = ["John", "Tom", "Json"]
    counts = [81, 94, 78]
    
    for name, count in zip(names, counts):  # 惰性生成
        print(name, count)

    # John 81
    # Tom 94
    # Json 78

最短的耗尽，zip就会终止

    names = ["John", "Tom", "Json", "Dave"]
    counts = [81, 94, 78]
    
    for name, count in zip(names, counts):
        print(name, count)

    # John 81
    # Tom 94
    # Json 78

`zip_longest` 会遍历完每个可迭代对象

    
    from itertools import zip_longest

    names = ["John", "Tom", "Json", "Dave"]
    counts = [81, 94, 78]
    
    for name, count in zip_longest(names, counts):
        print(name, count)

    # John 81
    # Tom 94
    # Json 78
    # Dave None